A single mole of AgNo3 weighs 169.88 grams. In order to make a 1M solution, how many grams of AgNo3 would need to be dissolved in 5oomL?

How many moles do you need?

moles = M x L.

How many grams is that?
moles = grams/molar mass.

84.94moles

To find out how many grams of AgNo3 would need to be dissolved in 500mL to make a 1M solution, we need to use the formula:

Molarity (M) = moles of solute / volume of solution (L)

We know that the molar mass of AgNo3 is 169.88 g/mol. So, one mole of AgNo3 weighs 169.88 grams.

First, let's calculate the number of moles required using the formula:

moles = Molarity * volume of solution (L)

Given that the volume of the solution is 500 mL (which is equal to 0.5 L), and the desired Molarity is 1M, we can substitute these values into the formula:

moles = 1M * 0.5 L = 0.5 moles

Now that we know the number of moles required, we can convert it to grams using the molar mass of AgNo3:

grams = moles * molar mass

grams = 0.5 moles * 169.88 g/mol = 84.94 grams

Therefore, in order to make a 1M solution, you would need to dissolve 84.94 grams of AgNo3 in 500mL (0.5L) of solution.