factor x2-3x+4
(x-4)(x+1)
i tried that one it doesn't work because that equals x2-3x-4 I need x2-3x+4
Sorry she made a mistake you need to use the quadratic formula which you can find on youtube.
will that help me to factor the equation because I did it and I got 3+ or - 5i all over 2 and that's not going to help me factor the equation
Well, it does.
x= -b+-sqrt(b^2-4ac) /2
x=3/2 +- 1/2 sqrt (9-16)
x= 1.5 +-i/2 sqrt7
(x-1.5+isqrt7/4)(x-1.5-isqrt7/4)
check that.
Unless the expression was
x²-4x+3
which you can factor.
Check the question.
To factor the quadratic expression x^2 - 3x + 4, we'll look for two binomials that, when multiplied together, result in the given expression.
Let's assume that the two binomials are in the form (x + a) and (x + b), where "a" and "b" are constants that we need to find.
Multiplying the two binomials, we have:
(x + a)(x + b) = x^2 + ax + bx + ab
Simplifying this expression, we get:
x^2 + (a + b)x + ab
Comparing this with the original expression x^2 - 3x + 4, we can see that (a + b) should be -3 and ab should be 4.
Now, we need to find two numbers whose sum is -3 and product is 4. After some trial and error, we find that the numbers -4 and 1 satisfy these conditions:
-4 + 1 = -3 (sum)
-4 × 1 = 4 (product)
Therefore, we can rewrite the quadratic expression as:
x^2 - 3x + 4 = (x - 4)(x + 1)
So, the factored form of x^2 - 3x + 4 is (x - 4)(x + 1).