What is the force of Friction as a 12 kg object slides down for 30 meters down a 30 degrees incline at a constant velocity?
To calculate the force of friction acting on a sliding object, we need to consider the normal force and the coefficient of friction.
1. Calculate the normal force:
The normal force is the force exerted by a surface to support the weight of an object resting on it. On an inclined plane, the normal force is perpendicular to the plane’s surface. In this case, the normal force is equal to the component of the object's weight perpendicular to the incline. To calculate the normal force, use the formula:
Normal force (N) = mass (m) x gravitational acceleration (g) x cosine of the angle (θ)
Given:
Mass (m) = 12 kg
Gravitational acceleration (g) = 9.8 m/s^2
Angle (θ) = 30 degrees
Normal force = 12 kg x 9.8 m/s^2 x cos(30 degrees)
2. Calculate the force of friction:
The force of friction can be determined using the formula:
Force of friction (Ff) = coefficient of friction (μ) x normal force
Since the object is sliding at a constant velocity, it means the friction force is equal to the applied force that balances it out, resulting in zero net force. So, the force of friction can be calculated as follows:
Force of friction (Ff) = 0
Therefore, the force of friction acting on the 12 kg object sliding down a 30-degree incline at a constant velocity is 0 Newtons.