a dailly farmer produce 50 tons of rice in the first day, 57 tons in the second day, and 64 tons in the third day. the production continue to increase in the same manner up to the 28 day. what is the
a) production of the farmer on the 28 day?
b) what is the total production of the farmer during this period
looks like an arithmetic sequence with
a = 50
d = 7
a) term(28) = a + 27d = 50 + 27(7) = ....
b) sum(28) =
you should have a formula for that.
To find the production on the 28th day, we first need to find the pattern in the increase. The production is increasing by 7 tons each day, starting from the first day with 50 tons.
To calculate the production on the 28th day, we can use the formula:
Production on the nth day = Initial production + (n - 1) * Increase per day
Using the formula, we can substitute the values we have:
Production on the 28th day = 50 + (28 - 1) * 7
= 50 + 27 * 7
= 50 + 189
= 239 tons
Therefore, the production on the 28th day is 239 tons.
To find the total production during this 28-day period, we can use the formula for the sum of an arithmetic sequence:
Total production = (First term + Last term) * Number of terms / 2
In this case, the first term is 50 tons, the last term is 239 tons, and the number of terms is 28.
Total production = (50 + 239) * 28 / 2
= 289 * 28 / 2
= 8084 tons
Therefore, the total production of the farmer during this 28-day period is 8084 tons.