a. How many moles of Na2Co3 were present in the 15mL sample?
b. How many grams of Na2CO3 were present in the 15mL sample?
c.How many grams of Na2CO3 are present in the 575L of the Na2CO3 solution?
See my response below. I assume you have a molarity somewhere in the problem but we can't help if you don't tell us more about the problem.
This is a Lab Report on Stoichiometry and Gravimetric Analysis.
I have a balance equation for the reaction. Na2Co3+ CaCl2--> CaCo3+ 2NaCl. (CHALK)
I think I know the Precipitate: Na2Co3 and CaCl2
- Calulate the dry precipitate and the mole of the precipitate produced in the reaction? (I Don't Understand)
I don't know the Empirical Formula.
That information helps a little but not enough to help you much. CaCO3 is the precipitate. All three of the other reagents are soluble. Usually in an analysis like this, you are given a mass of the precipitate, in this case CaCO3, and asked to calculate mols and percent Na2CO3. You have the empirical formulas of all four reagents listed correctly.
Thanx for the Help
Quick Question what is the dry Precipitate?
The dry ppt is the CaCO3 after it has been dried, usually in an oven. You probably weighed the dry ppt and you have a mass for it.
To answer these questions, we need to use the given information about the sample volume and the concentration of Na2CO3. Then we can use the concept of moles and molar mass to calculate the number of moles or grams of Na2CO3.
a. To calculate the number of moles of Na2CO3 in the 15 mL sample, we first need to know the concentration of Na2CO3 in the solution. If the concentration is given, for example, in moles per liter (M), we can multiply it by the volume in liters to find the number of moles.
b. If we know the number of moles of Na2CO3 in the 15 mL sample, we can calculate the mass of Na2CO3 by multiplying the number of moles by the molar mass of Na2CO3. The molar mass of Na2CO3 can be determined by adding up the atomic masses of Na (sodium) and CO3 (carbonate).
c. To find the grams of Na2CO3 in the 575 L solution, we can follow a similar procedure as in part (a). Determine the concentration of Na2CO3 in moles per liter, then multiply it by the volume in liters to obtain the number of moles. Finally, multiply the number of moles by the molar mass of Na2CO3 to find the mass in grams.