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A bullet leaves a rifle with a muzzle velocity of 521 m/s. While accelerating through the barrel of the rifle, the bullet moves a distance of 0.840 m. Determine the acceleration of the bullet (uniform acceleration)

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  1. V^2 = 2ad = (521)^2,
    2a*0.84 = 271441,
    168a = 271441,
    a = 271441 / 1.68 = 161572 m/s^2.

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  2. Thanks but on topper website it is solved in another way which seems correct. I want to understand that way....Could you explain?

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  3. Henry just used the equation V2² = V1² + 2ad where V1 (Initial velocity) is 0. Therefore it is shortened to:
    V2² = 2ad
    V2² / (2d) = a

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