If Michael Jordan has a vertical leap of 1.29 m, then what is his takeoff speed and his hang time?

To determine Michael Jordan's takeoff speed and hang time, we'll need to make a few calculations.

First, let's start by finding the takeoff speed.

Takeoff speed is the initial velocity with which Michael Jordan leaves the ground. We can use the equation:

v^2 = u^2 + 2as

where:
v = final velocity (0 m/s at the peak of the jump)
u = initial velocity (takeoff speed)
a = acceleration due to gravity (-9.8 m/s^2)
s = displacement (vertical leap of 1.29 m)

Rearranging the equation to solve for u, we have:

u = √(v^2 - 2as)

Since v = 0 m/s, the equation simplifies to:

u = √(0^2 - 2(-9.8)(1.29))

Calculating this, we find:

u ≈ √(0 - 2(-9.8)(1.29)) ≈ √(25.284) ≈ 5.03 m/s

Therefore, Michael Jordan's takeoff speed is approximately 5.03 m/s.

Now, let's find the hang time, which is the amount of time Michael Jordan spends in the air.

Hang time can be calculated using the equation:

t = (v - u) / a

where:
t = time in seconds
v = final velocity (0 m/s at the peak of the jump)
u = initial velocity (takeoff speed)
a = acceleration due to gravity (-9.8 m/s^2)

Since we already know u and v, we can substitute them into the equation:

t = (0 - 5.03) / (-9.8)

Calculating this, we get:

t ≈ (-5.03) / (-9.8) ≈ 0.513 seconds

Therefore, Michael Jordan's hang time is approximately 0.513 seconds.

To calculate Michael Jordan's takeoff speed, you can use the following formula:

v = √(2 * g * h)

Where:
v represents the takeoff speed,
g represents the acceleration due to gravity (approximately 9.8 m/s²),
h represents the vertical leap (1.29 m).

Using these values:

v = √(2 * 9.8 * 1.29)

v ≈ 5.02 m/s

Therefore, Michael Jordan's takeoff speed is approximately 5.02 m/s.

To find the hang time, you can use the following formula:

t = (2 * v) / g

Where:
t represents the hang time,
g represents the acceleration due to gravity (approximately 9.8 m/s²),
v represents the takeoff speed (5.02 m/s).

Using these values:

t = (2 * 5.02) / 9.8

t ≈ 1.02 seconds

Therefore, Michael Jordan's hang time is approximately 1.02 seconds.

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