CH3COOH + C5H12O -> C7H14O2 + H2O
If the yield for the reaction is 45%, how many grams of the product are formed when 3.58 g of acetic acid are reacted with 4.75 grams of isopentyl alcohol?
Millimoles of acetic acid= 59.6667
Millimoles of isopentyl alcohol= 53.9773
How would I convert mmoles acetic acid to mmoles of the product and mmoles isopentyl alcohol to mmoles of the product?
Would I take the millimoles of each(acetic acid and isopentyl alcohol) and multiply that value by the molecular weight of the products (148 g/mol)?
To convert mmoles of one item to mmoles of another item, you use the coefficients in the balanced equation.
mmoles acetic acid = about 59.7; therefore,
59.7 mmoles acetic acid x (1 mole isopentyl acetate/1 mole acetic acid) = mmoles isopentyl actate.
??mmoles isopentyl alcohol x (1 mole product/1 mole isopentyl alcohol) = moles product.
g product = moles product x molar mass product.
To convert millimoles of acetic acid to millimoles of the product, you would need to use the stoichiometry of the balanced chemical equation. In this case, the stoichiometry tells us that one mole of acetic acid (CH3COOH) reacts with one mole of isopentyl alcohol (C5H12O) to produce one mole of the product (C7H14O2).
Therefore, to convert millimoles of acetic acid to millimoles of the product, you would multiply the millimoles of acetic acid by the molar ratio of the product to acetic acid, which is 1:1.
Similarly, to convert millimoles of isopentyl alcohol to millimoles of the product, you would also multiply the millimoles of isopentyl alcohol by the molar ratio of the product to isopentyl alcohol, which is also 1:1.
So, no, you do not need to multiply by the molecular weight of the product to convert millimoles of acetic acid and isopentyl alcohol to millimoles of the product.
To convert millimoles of acetic acid (CH3COOH) to millimoles of the product (C7H14O2), you would need to determine the stoichiometric ratio between acetic acid and the product.
From the balanced chemical equation:
CH3COOH + C5H12O -> C7H14O2 + H2O
The stoichiometric ratio between CH3COOH and C7H14O2 is 1:1. This means that for every mole of CH3COOH, you would expect to produce 1 mole of C7H14O2.
Therefore, to convert millimoles of acetic acid to millimoles of the product, you can simply multiply the millimoles of acetic acid by the same ratio, which is 1:1.
Similarly, to convert millimoles of isopentyl alcohol (C5H12O) to millimoles of the product, you would also need to determine the stoichiometric ratio between isopentyl alcohol and the product.
From the balanced chemical equation:
CH3COOH + C5H12O -> C7H14O2 + H2O
The stoichiometric ratio between C5H12O and C7H14O2 is 1:1. This means that for every mole of C5H12O, you would expect to produce 1 mole of C7H14O2.
Therefore, to convert millimoles of isopentyl alcohol to millimoles of the product, you can simply multiply the millimoles of isopentyl alcohol by the same ratio, which is 1:1.
Once you have converted the millimoles of acetic acid and isopentyl alcohol to millimoles of the product, you can then multiply this value by the molecular weight of the product (148 g/mol) to obtain the mass of the product formed.