Two strong magnets on opposite sides of a small table are shown. The long-range attractive force between the magnets keeps the lower magnet in place. Suppose the weight of the table is 23.4 N, the weight of each magnet is 2.67 N, and the magnetic force on the lower magnet is 5.71 times its weight.Find the magnitude of the force of the upper magnet on the lower magnet.
To find the magnitude of the force of the upper magnet on the lower magnet, we can use the information given in the problem.
Let's denote the weight of each magnet as Wm and the weight of the table as Wt. We have the following values:
Wm = 2.67 N (weight of each magnet)
Wt = 23.4 N (weight of the table)
The problem also states that the magnetic force on the lower magnet is 5.71 times its weight. So, we can write that force as:
Fm = 5.71 * Wm
To find the magnitude of the force of the upper magnet on the lower magnet, we need to find the net force acting on the lower magnet. Since the only two forces acting on it are the weight of the magnet (Wm) and the magnetic force (Fm), the net force is given by:
Net Force = Fm - Wm
Substituting the values we have:
Net Force = (5.71 * Wm) - Wm
Now, we can calculate the magnitude of the force of the upper magnet on the lower magnet.