For the reaction shown, compute the theoretical yield of the product (in grams) Ti(s)+2Fe(g) = TiF2(s)
6.0 g Ti, 6.0g F2
1. Convert 6.0 g Ti to moles. moles = grams/molar mass
2. Convert 6.0 g F2 to moles. Same process.
3a. Using the coefficients in the balanced equation, convert moles Ti to moles of the product.
3b. Same process, convert moles F2 to moles of the product.
3c. I expect the answers to 3a and 3b will not agree which means one of them is wrong. The correct answer in limiting reagent problems is ALWAYS the smaller one and the reagent responsible for producing that result is the limiting reagent.
4. Using the smaller value from 3c above, convert that value to grams. g = moles x molar mass.
thank you so much. I needed a mind referesher ;-)
To calculate the theoretical yield of the product, you need to determine which reactant is limiting and then use the stoichiometry of the balanced chemical equation to find the moles of the limiting reactant and finally convert it to grams.
1. Begin by balancing the chemical equation:
Ti(s) + 2Fe(g) -> TiF2(s)
2. Find the molar mass of the given substances:
- Molar mass of Ti: 47.87 g/mol
- Molar mass of F2: 38.00 g/mol
3. Calculate the number of moles for each reactant:
- Moles of Ti = mass of Ti / molar mass of Ti
= 6.0 g / 47.87 g/mol
= 0.125 moles
- Moles of F2 = mass of F2 / molar mass of F2
= 6.0 g / 38.00 g/mol
= 0.158 moles
4. Determine the limiting reactant:
The limiting reactant is the one that is completely consumed and restricts the amount of product formed. To find the limiting reactant, compare the moles of each reactant to their stoichiometric ratio in the balanced equation.
The balanced equation shows that 1 mole of titanium (Ti) reacts with 2 moles of Fe to form 1 mole of titanium fluoride (TiF2).
The mole ratio of Ti to Fe is 1:2.
From the calculations:
- Moles of Ti = 0.125 moles
- Moles of Fe = 0.158 moles
Since the stoichiometric ratio between Ti and Fe is 1:2, it means that 0.125 moles of Ti would theoretically react with 0.25 moles of Fe (double the amount of Ti). However, we only have 0.125 moles of Ti and 0.158 moles of Fe, which is slightly more than 0.25 moles of Fe. This means that Ti is the limiting reactant, as it would completely react with all the available Fe.
5. Calculate the theoretical yield of the product (TiF2):
To find the theoretical yield of TiF2, we need to calculate the moles of TiF2 that would be formed from the limiting reactant (Ti).
From the balanced equation, we know that 1 mole of Ti forms 1 mole of TiF2. Therefore, using the limiting reactant's moles:
- Moles of TiF2 = Moles of Ti
= 0.125 moles
6. Convert moles of TiF2 to grams:
To convert moles to grams, multiply the moles by the molar mass of TiF2.
- Molar mass of TiF2: (1 x molar mass of Ti) + (2 x molar mass of F)
= (1 x 47.87) + (2 x 38.00)
= 47.87 + 76.00
= 123.87 g/mol
- Theoretical yield (TiF2) = Moles of TiF2 x Molar mass of TiF2
= 0.125 moles x 123.87 g/mol
= 15.48 grams
Therefore, the theoretical yield of TiF2 from 6.0 g of Ti and 6.0 g of F2 is 15.48 grams.