How do you solve

log(5) 20 + log (5) 10 - 3log(5) 2?

z = log(5) [200/8] = log(5)[25]

5^z = 25

z = 2

To solve the given expression, we can apply the properties of logarithms. In this case, we will use the properties of logarithms to simplify the expression.

First, let's recall the properties of logarithms:

1. Logarithm of a product: log(base a) (xy) = log(base a) x + log(base a) y
2. Logarithm of a quotient: log(base a) (x/y) = log(base a) x - log(base a) y
3. Logarithm of an exponent: log(base a) (x^y) = y * log(base a) x

Now, let's solve the given expression step by step:

1. log(base 5) 20 + log(base 5) 10 - 3 log(base 5) 2

2. Applying the logarithm of a product property to the first two terms:
log(base 5) (20 * 10) - 3 log(base 5) 2

3. Simplifying the product:
log(base 5) 200 - 3 log(base 5) 2

4. Applying the logarithm of an exponent property to the last term:
log(base 5) 200 - log(base 5) (2^3)

5. Simplifying the exponent:
log(base 5) 200 - log(base 5) 8

6. Using the logarithm of a quotient property:
log(base 5) (200/8)

7. Simplifying the division:
log(base 5) 25

8. Since 5^2 = 25, the final answer is 2.

Therefore, the solution to the given expression log(base 5) 20 + log(base 5) 10 - 3 log(base 5) 2 is equal to 2.