the area of a rectangle is 60cm.the length is 11cm more than the width. find the width.
Width=w
Length=w+11
w(w+11)=60
w^2+11w-60=0
(w-4)(w+15)=0
w=4cm
width --- x
length --- x+11
solve x(x+11) = 60
the quadratic factors very nicely,
you will get a positive and a negative answer.
reject the negative answer.
Maths answer
understandable well done
Okay then .
Width=-y
Length=-y+11
Y(y+11) =60cm
Y²+11y=60
Y²+11y-60=0
Then solve the quadratic equation
Note that the width cannot be a negative number
To solve the quadratic equation Y²+11y-60=0, we can factorize it:
(Y-4)(Y+15)=0
This gives us two possible values for the width, Y=4 and Y=-15. However, since the width cannot be negative, the width of the rectangle is 4cm.
Therefore, the width of the rectangle is 4cm.
The area of a rectangle is 60cm . the length is 11cm more than the width. Find the width
Width=-y
Length=-y+11
Y(y+11) =60cm
Y²+11y=60
Y²+11y-60=0
Then solve the quadratic equation
Note that the width cannot be a negative number