What is the volume of 3.5 moles of oxygen gas (O2) at standard temperature and pressure (STP)?
6.4 L
22.4 L
32.0 L
78.4 L
I thought I did this for you about 25 posts back.
22.4 L/mole x 3.5 moles = ?? L
78.4 liters thank you!
To calculate the volume of a gas at STP, you can use the ideal gas law equation, which is PV = nRT, where P is the pressure, V is the volume, n is the number of moles of the gas, R is the ideal gas constant, and T is the temperature in Kelvin.
At STP, the pressure is 1 atmosphere (atm) and the temperature is 273.15 Kelvin (K).
First, convert the temperature to Kelvin by adding 273.15:
T = 0 + 273.15 = 273.15 K
Next, we can rearrange the equation to solve for V:
V = nRT / P
Plug in the values:
n = 3.5 moles
R = 0.0821 L·atm/(mol·K)
P = 1 atm
T = 273.15 K
V = (3.5 moles)(0.0821 L·atm/(mol·K))(273.15 K) / (1 atm)
Simplifying the equation:
V = 95.924 L
Therefore, the volume of 3.5 moles of oxygen gas at STP is approximately 95.924 L.
None of the given answer choices match this calculated volume, so it seems that there may be an error in the provided options.