What is the volume of 3.5 moles of oxygen gas (O2) at standard temperature and pressure (STP)
22.4 L/mol x 3.5 moles = ??
To find the volume of 3.5 moles of oxygen gas (O2) at standard temperature and pressure (STP), we need to use the ideal gas law equation:
PV = nRT
Where:
P is the pressure
V is the volume
n is the number of moles
R is the ideal gas constant (8.31 J/(mol·K))
T is the temperature in Kelvin
At STP, the pressure is 1 atmosphere (atm) and the temperature is 273.15 Kelvin (K). Therefore, we can substitute these values into the ideal gas law equation:
(1 atm) * V = (3.5 moles) * (8.31 J/(mol·K)) * (273.15 K)
To solve for V, we rearrange the equation:
V = (3.5 moles) * (8.31 J/(mol·K)) * (273.15 K) / (1 atm)
Calculating this expression will give us the volume of 3.5 moles of oxygen gas at STP.