if one number is four more than twice the second number and the total is twenty five what are the numbers?
Let x equal the first number.
x + 2x + 4 = 25
3x = 21
x = ?
x=25
x+2x+4=25
3X+4=25
3x=21
(divide 21 by 3)
x=21/3
x=7
To find the two numbers, we can set up a system of equations based on the given information.
Let's assume the first number is represented by "x" and the second number is represented by "y".
From the given information, we can set up the following equations:
1) "One number is four more than twice the second number" can be expressed as:
x = 2y + 4
2) "The total is twenty-five" can be expressed as:
x + y = 25
Now we have a system of two equations with two variables. We can solve these equations to find the values of x and y.
One way to solve this system is by substitution method. We can use equation 1) to substitute the value of x in equation 2).
From equation 1), we have x = 2y + 4. We substitute this value in equation 2):
(2y + 4) + y = 25
3y + 4 = 25
3y = 25 - 4
3y = 21
Now, we divide both sides of the equation by 3:
y = 21 / 3
y = 7
Substituting the value of y back into equation 1):
x = 2y + 4
x = 2(7) + 4
x = 14 + 4
x = 18
Therefore, the two numbers are x = 18 and y = 7.