A shuffle board table is 5 feet tall. A puck slides off the table at 2 m/s. how long before it hits the ground?
To find the time it takes for the puck to hit the ground, we can use the equations of motion. The equation that relates the initial velocity, final velocity, time, and displacement is:
\[v_f = v_i + at\]
Where:
- \(v_f\) is the final velocity (in this case, 0 m/s, since the puck will come to rest on the ground).
- \(v_i\) is the initial velocity of the puck (2 m/s).
- \(a\) is the acceleration due to gravity (-9.8 m/s², as the puck is pulled downwards by gravity).
- \(t\) is the time we want to find.
To solve for \(t\), we rearrange the equation:
\[t = \frac{{v_f - v_i}}{{a}}\]
Substituting the given values:
\[t = \frac{{0 - 2}}{{-9.8}}\]
Now we can calculate the time it takes for the puck to hit the ground:
\[t = \frac{{-2}}{{-9.8}} = 0.204\,s\]
Therefore, it takes approximately 0.204 seconds for the puck to hit the ground.