a molar elipticity [q]466 nm, 25 �C
of D(−) − Co(en)3I3.H2O and obtained -5940 deg.cm2.decimol-1. Calculate the
elipticity angleq (in mdeg) assuming they dissolved 0.25 g sample in 5 mL of
H2O and used a 1 x 1 cm cuvette.
(
To calculate the ellipticity angle (q) in millidegrees (mdeg), we need to use the given values of molar ellipticity ([q]), wavelength (l), temperature (T), sample weight (w), sample volume (V), and cuvette path length (b).
Given:
Molar ellipticity ([q]): 466 nm
Temperature (T): 25 °C
Sample weight (w): 0.25 g
Sample volume (V): 5 mL
Cuvette path length (b): 1 cm
The formula to calculate the ellipticity angle (q) is:
q = ([q] x w x l) / (V x b)
Now, let's plug in the given values:
q = (466 nm x 0.25 g x 1 cm) / (5 mL x 1 cm)
First, we need to convert the volume from mL to cm^3:
1 mL = 1 cm^3
q = (466 nm x 0.25 g x 1 cm) / (5 cm^3 x 1 cm)
Next, we need to convert the wavelength from nm to cm:
1 nm = 10^-7 cm
q = (466 x 10^-7 cm x 0.25 g x 1 cm) / (5 cm^3 x 1 cm)
Calculating the values:
q = (1.165 x 10^-7 cm^2.g / cm^4)
Finally, taking the inverse of the value to convert cm^4 to cm^2 and multiplying by 1000 to convert to millidegrees (mdeg):
q = -5940 mdeg
Therefore, the ellipticity angle (q) assuming a 0.25 g sample dissolved in 5 mL of H2O and using a 1 x 1 cm cuvette is -5940 mdeg.