Acetic acid (CH3COOH) reacts with isopentyl alcohol (C5H12O) to form isopentyl acetate (C7H14O2), a fragrant substance with the odor of bananas.
CH3COOH + C5H12O -> C7H14O2 + H2O
If the yield for the reaction is 45%, how many grams of the product are formed when 3.58 g of acetic acid are reacted with 4.75 grams of isopentyl alcohol?
To find the number of grams of the product formed, we need to calculate the number of moles of reactants and then use the balanced equation to determine the number of moles of the product. Finally, we can convert the moles of the product to grams.
Let's start by calculating the number of moles of acetic acid (CH3COOH) and isopentyl alcohol (C5H12O) used in the reaction.
1. Calculate the moles of acetic acid (CH3COOH):
Moles = mass / molar mass
Given mass of acetic acid = 3.58 g
Molar mass of acetic acid (CH3COOH) = 60.05 g/mol
Moles of acetic acid = 3.58 g / 60.05 g/mol
2. Calculate the moles of isopentyl alcohol (C5H12O):
Given mass of isopentyl alcohol = 4.75 g
Molar mass of isopentyl alcohol (C5H12O) = 88.15 g/mol
Moles of isopentyl alcohol = 4.75 g / 88.15 g/mol
Now, we can use the balanced equation to determine the stoichiometry between the reactants and the product.
The balanced equation is:
CH3COOH + C5H12O -> C7H14O2 + H2O
From the balanced equation, we can see that the mole ratio between acetic acid (CH3COOH) and isopentyl acetate (C7H14O2) is 1:1. This means that for every mole of acetic acid used, we will get one mole of isopentyl acetate as the product.
Next, we need to calculate the moles of isopentyl acetate formed using the moles of acetic acid.
3. Moles of isopentyl acetate formed = Moles of acetic acid used
Now, we can convert the moles of isopentyl acetate to grams using the molar mass of isopentyl acetate (C7H14O2).
4. Calculate the mass of isopentyl acetate formed:
Moles of isopentyl acetate formed * Molar mass of isopentyl acetate
To find the actual yield, multiply the mass of isopentyl acetate formed by the percent yield (45% = 0.45).
5. Calculate the final mass of the product formed:
Mass of isopentyl acetate formed * Percent yield
By following these steps, you should be able to calculate the grams of the product formed when 3.58 g of acetic acid reacts with 4.75 grams of isopentyl alcohol.