What is the wavelength of radiation that has a frequency of 6.912 × 10^14 s−1?
and does the s-1 make a difference?
Thank you!
The s-1 is the unit and it's read as
6.912 X 10^14 per second.
c = frequency x wavelength.
You know c and frequency, calculate wavelength.
To find the wavelength of radiation with a frequency of 6.912 × 10^14 s−1, you can use the wave equation:
c = λν
Where:
- c is the speed of light (approximately 3.00 × 10^8 m/s)
- λ is the wavelength of the radiation
- ν is the frequency of the radiation
You are given the frequency (ν), so you can rearrange the equation to solve for the wavelength (λ):
λ = c/ν
Substituting the values into the equation:
λ = (3.00 × 10^8 m/s)/(6.912 × 10^14 s−1)
λ ≈ 4.34 × 10^-7 meters
So, the wavelength of radiation with a frequency of 6.912 × 10^14 s−1 is approximately 4.34 × 10^-7 meters.
Regarding your question about the "s-1" term, it represents the unit of seconds raised to the power of -1, which indicates frequency as cycles or events per second. It does make a difference because frequency is a measure of how many waves pass a given point in one second. The "s-1" unit is known as Hertz (Hz). It is important to include the unit to clearly define the quantity being discussed.