NaI(aq)+Hg(C2H3O2)2(aq) complete and balance complete equation

2NaI + Hg(C2H3O2)2 ==> HgI2 + 2NaC2H3O2

To balance the complete equation for the reaction between NaI(aq) and Hg(C2H3O2)2(aq), we need to ensure that the number of atoms of each element is balanced on both sides of the equation.

First, let's write the given reaction:

NaI(aq) + Hg(C2H3O2)2(aq) → ?

Looking at the reactants, we have one sodium atom on the left side and two acetate (C2H3O2) ions. On the right side, we have no sodium atoms but two acetate ions as well. To balance the sodium atoms, we'll need to put a coefficient of 2 in front of NaI, resulting in:

2 NaI(aq) + Hg(C2H3O2)2(aq) → ?

Next, let's balance the iodine atoms. There are two iodine atoms on the left side, so we'll need two iodine atoms on the right side. To achieve this, we'll need to put a coefficient of 2 in front of HgI2:

2 NaI(aq) + 2 Hg(C2H3O2)2(aq) → ?

Now, let's balance the hydrogen atoms. There are eight hydrogen atoms coming from the acetate ions on the left side, so we'll need eight hydrogen atoms on the right side as well. To accomplish this, we'll put a coefficient of 4 in front of the water (H2O) product:

2 NaI(aq) + 2 Hg(C2H3O2)2(aq) → 4 H2O(l) + 2 HgI2(aq)

Finally, let's balance the oxygen atoms. We have four oxygen atoms from the water on the right side of the equation. To balance this, we'll need four oxygen atoms on the left side. We can achieve this by adding a coefficient of 4 in front of NaI:

4 NaI(aq) + 2 Hg(C2H3O2)2(aq) → 4 H2O(l) + 2 HgI2(aq)

The balanced equation is:

4 NaI(aq) + 2 Hg(C2H3O2)2(aq) → 2 HgI2(aq) + 4 H2O(l)

To balance the equation NaI(aq) + Hg(C2H3O2)2(aq), we need to ensure that the number of atoms on both sides of the equation is equal.

First, let's write the chemical formulas correctly:
NaI(aq) + Hg(C2H3O2)2(aq)

Now, let's balance the equation step by step.

1. Balance the sodium (Na) atoms by placing a coefficient of 2 in front of NaI:
2NaI(aq) + Hg(C2H3O2)2(aq)

2. Balance the iodine (I) atoms by placing a coefficient of 2 in front of HgI2:
2NaI(aq) + HgI2(aq)

3. Now, let's balance the mercury (Hg) atoms. We have 1 Hg atom on the left side and 2 Hg atoms on the right side. To balance it, place a coefficient of 2 in front of HgI2:
2NaI(aq) + 2HgI2(aq)

4. Lastly, let's balance the acetate (C2H3O2) ions. We have 2 acetate ions on the right side, so we need to place a coefficient of 2 in front of NaC2H3O2:
2NaI(aq) + 2HgI2(aq) + 2NaC2H3O2(aq)

The balanced equation is:
2NaI(aq) + 2HgI2(aq) + 2NaC2H3O2(aq)

This means that when sodium iodide reacts with mercury(II) acetate, it forms mercury(II) iodide and sodium acetate.