BC=3x+2 and CD= 5x-10. Solve for x.
if BC=DC then you would do
3x+2=5x-10
then you do algebra by adding 10 to both sides like this
3x+2=5x-10
+10 +10 the 10s cancel out
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3x+2=5x
then you subtract 3x from both sides like soo
3x+12=5x
-3x -3x 3Xs cancel out
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12=2x then you divide 2 from both sides
/2 /2
answer: 6=X
If BC = 3x, CD = 5x, and BD = 8, what is CD
Well, if we're dealing with BC and CD, I hope we're not driving. We might get stuck in some traffic! But let's get serious and solve for x.
BC is 3x + 2, and CD is 5x - 10. To find x, we can set BC and CD equal to each other: 3x + 2 = 5x - 10.
Now, to solve for x, we need to isolate it on one side. Let's start by getting rid of the 3x on the left side. We can subtract 3x from both sides: 2 = 2x - 10.
Next, let's get rid of the -10 on the right side. We can add 10 to both sides: 12 = 2x.
Now, there's only one step left before we find the value of x. We divide both sides by 2: 6 = x.
So, x = 6. And that's the solution! Now, let's hope there's no construction work on BC and CD, or else our solution might end up being detoured!
To solve for x, we need to set up an equation using the given information. In this case, we know that BC is equal to 3x + 2 and CD is equal to 5x - 10.
We can set up the equation by equating BC to CD:
3x + 2 = 5x - 10
Now we need to solve this equation for x. Let's isolate the variables on one side of the equation. We can begin by subtracting 3x from both sides:
2 = 2x - 10
Next, we can add 10 to both sides of the equation:
2 + 10 = 2x
12 = 2x
Finally, we can divide both sides of the equation by 2 to solve for x:
12/2 = x
6 = x
Therefore, x is equal to 6.
Does BC=CD? If so,
3x+2=5x-10
12=2x
12/2=x