200g of water (specific heat of 4.184 Jg-1'c-1) loses 2000 J of heat. Its starting temperature is 70'C. Calculate the temperature of the water.
mass water x specific heat water x (Tfinal-Tinitial) = q = -2000 J.
Solve for Tfinal
2000J=200g*4.184J/gC*(Tf-70C)
solve for Tf
Calculate the heat in kilojoules needed to vaporize 2.00g of water at 100 celcius.
To calculate the final temperature of the water, we can use the formula:
Q = m * c * ΔT
Where:
Q is the heat transferred (in Joules),
m is the mass of the water (in grams),
c is the specific heat capacity of water (in Joules per gram-degree Celsius),
ΔT is the change in temperature (in degrees Celsius).
In this case, the heat transferred (Q) is given as 2000 J, the mass (m) is 200 g, and the specific heat capacity of water (c) is 4.184 J/g°C. The initial temperature (T1) is 70°C, and we want to find the final temperature (T2).
We can rearrange the formula to solve for ΔT:
ΔT = Q / (m * c)
Substituting the given values:
ΔT = 2000 J / (200 g * 4.184 J/g°C)
Calculating the value of ΔT:
ΔT = 2.39 °C
Finally, we can find the final temperature by adding ΔT to the initial temperature:
T2 = T1 + ΔT
T2 = 70°C + 2.39°C
Therefore, the final temperature of the water is approximately 72.39°C.