calculate the discriminant of
3x^2 - 4x + 2
Jake/Jim, please do not switch names. See the other post.
To calculate the discriminant of a quadratic equation in the form ax^2 + bx + c, you can use the equation: Δ = b^2 - 4ac.
For the equation 3x^2 - 4x + 2, let's identify the values of a, b, and c:
a = 3
b = -4
c = 2
Now, we can substitute these values into the discriminant formula:
Δ = (-4)^2 - 4(3)(2)
Next, we simplify the expression:
Δ = 16 - 24
Finally, we calculate the discriminant:
Δ = -8
Therefore, the discriminant of the quadratic equation 3x^2 - 4x + 2 is -8.