on a level road the stopping distance for an automobile is 35.0m for an initail speed of 90 km/hr what is the stopping distance of the same automobile on a simalr road with the slope 1:10
Assume the coefficent of friction is the same.
F=mu*Normal force=ma
a= normalforce*mu/mass
Vf^2=Vi^2+2ad
solve for mu on the level road, knowing normalforce is mg.
Then, knowingmu, look at the slope
normal force=mg*SinTheta
Vf^2=Vi^2+2mgSinTheta*mu/m * d
solve for distance.
since Theta is a small angle, SinTheta=TanTheta= 1/10