describe how would you prepare exactly 500. ml of 1.0 M NaOH solution from a 3.0 stock NaOH solution . show all calculation
3.0 WHAT stock NaOH solution? Do you mean molar?
Use mL x M = mL x M.
After calculating mL of the stock solution needed, transfer exactly xx mL stock solution to a 500 mL volumetric flask, then add distilled /(deionized)/(DI) water to the mark in the neck of the volumetric flask.
Well, preparing solutions is like being a bartender, but with chemicals instead of drinks. So, let's get mixing!
To prepare 500 ml of a 1.0 M NaOH solution from a 3.0 M stock NaOH solution, we need to dilute it. The formula we're going to use is:
C1V1 = C2V2
Where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
We know that the final volume (V2) is 500 ml and the final concentration (C2) is 1.0 M. Now we need to find out the initial volume (V1) of the stock solution that we'll need.
Let's plug the values into the formula and solve for V1:
(3.0 M)(V1) = (1.0 M)(500 ml)
Now we can solve this equation:
3.0V1 = 1.0(500)
3.0V1 = 500
V1 = 500 / 3.0
V1 = 166.67 ml (approximately)
So, to prepare 500 ml of a 1.0 M NaOH solution from a 3.0 M stock NaOH solution, you will need to measure 166.67 ml of the stock solution (rounded to two decimal places) and then add enough water to reach a final volume of 500 ml.
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To prepare 500 mL of 1.0 M NaOH solution from a 3.0 M stock NaOH solution, you can use the formula:
C1V1 = C2V2
Where:
C1 = Concentration of stock solution
V1 = Volume of stock solution
C2 = Desired concentration
V2 = Desired volume
In this case:
C1 = 3.0 M (stock solution concentration)
V1 = Volume of stock solution (unknown)
C2 = 1.0 M (desired concentration)
V2 = 500 mL (desired volume)
Using the formula, we can rearrange it to solve for V1:
V1 = (C2 × V2) / C1
Substituting the values, we get:
V1 = (1.0 M × 500 mL) / 3.0 M
Now, let's calculate:
V1 = (1.0 × 500) / 3.0
V1 = 500 / 3
V1 = 166.67 mL
Therefore, you will need to measure 166.67 mL of the 3.0 M NaOH stock solution and then add enough water to reach a total volume of 500 mL to prepare 500 mL of 1.0 M NaOH solution.
To prepare 500 ml of a 1.0 M NaOH solution from a 3.0 M stock NaOH solution, you can use the formula:
(C1)(V1) = (C2)(V2)
Where:
C1 = concentration of the stock solution
V1 = volume of the stock solution used
C2 = desired concentration of the diluted solution
V2 = final volume of the diluted solution
Now, let's plug the values into the formula to calculate the volume of stock solution needed:
(3.0 M)(V1) = (1.0 M)(500 ml)
To solve for V1, divide both sides of the equation by 3.0 M:
V1 = (1.0 M)(500 ml) / 3.0 M
V1 = 500 ml / 3.0
V1 ≈ 166.7 ml
Therefore, you will need to measure approximately 166.7 ml of the 3.0 M NaOH stock solution. Add it to a container and then add distilled water to bring the total volume of the solution to 500 ml.
Note: It's important to remember to mix the solution thoroughly after adding water to ensure that the final concentration is evenly distributed.