Write balanced complete ionic equation for HC2H3O2(aq) + K2CO3(aq)-----> H2O(l)+CO2(g)+KC2H3O2(aq)
I put 2H+(aq)+2C2H3O2-2(aq)2K+(ag)+CO3-2(aq)------>H2O(l)+CO2(g)+2K+(aq)+C2H3O2-2(aq)
and said it was wrong, but I got this part right.
2H+(aq)+CO3 2-(aq)----->H2O(l)+CO2(g)
2H+(aq)+2C2H3O2−(aq)+2K+(aq)+CO32−(aq)→H2O(l)+CO2(g)+2C2H3O2−(aq)+2K+(aq)
Well, it seems like you're almost there! Let me help you balance the complete ionic equation for the reaction between HC2H3O2(aq) and K2CO3(aq).
First, let's start with the reactants:
HC2H3O2(aq) + K2CO3(aq)
Now, let's break them down into ions:
H+(aq) + C2H3O2-(aq) + 2K+(aq) + CO3-2(aq)
Next, let's write the products:
H2O(l) + CO2(g) + 2K+(aq) + C2H3O2-(aq)
Putting it all together, we have:
H+(aq) + C2H3O2-(aq) + 2K+(aq) + CO3-2(aq) -----> H2O(l) + CO2(g) + 2K+(aq) + C2H3O2-(aq)
And there you have it! The balanced complete ionic equation for the reaction between HC2H3O2(aq) and K2CO3(aq) is:
H+(aq) + C2H3O2-(aq) + 2K+(aq) + CO3-2(aq) -----> H2O(l) + CO2(g) + 2K+(aq) + C2H3O2-(aq)
Remember, ions that appear unchanged on both sides of the equation should be canceled out.
The correct balanced complete ionic equation for the reaction HC2H3O2(aq) + K2CO3(aq) → H2O(l) + CO2(g) + KC2H3O2(aq) is:
2 HC2H3O2(aq) + K2CO3(aq) → 2 H2O(l) + CO2(g) + 2 KC2H3O2(aq)
To write the balanced complete ionic equation, you need to break down all the reactants and products into their respective ions:
2 H+(aq) + 2 C2H3O2-(aq) + 2 K+(aq) + CO3^2-(aq) → 2 H2O(l) + CO2(g) + 2 K+(aq) + 2 C2H3O2^-(aq)
Note that the potassium ion (K+) and the acetate ion (C2H3O2-) are spectator ions, meaning they appear on both sides of the equation and do not participate in the overall reaction.
To write the balanced complete ionic equation for the reaction between HC2H3O2(aq) and K2CO3(aq), we first need to identify the ions present in each compound.
HC2H3O2(aq) dissociates into H+(aq) and C2H3O2-(aq).
K2CO3(aq) dissociates into 2K+(aq) and CO3^2-(aq).
Therefore, the complete ionic equation for the reaction would be:
2H+(aq) + CO3^2-(aq) + 2K+(aq) + 2C2H3O2^-(aq) → H2O(l) + CO2(g) + 2K+(aq) + 2C2H3O2^-(aq)
However, notice that the K+ and C2H3O2- ions are present on both sides of the equation. These ions do not undergo any chemical change and are therefore considered spectator ions. They can be eliminated to give the net ionic equation:
2H+(aq) + CO3^2-(aq) → H2O(l) + CO2(g)
The net ionic equation represents only the species that participate in the reaction and is useful for focusing on the actual chemical change occurring.