An aircraft on its take-off run has a uniform acceleration of 3m/s^2.What velocity does the aircraft gain in 4s?
To find the velocity gained by the aircraft in 4 seconds, we can use the equation of motion:
v = u + at
Where:
v = final velocity
u = initial velocity
a = acceleration
t = time
In this case, the aircraft is on its take-off run, so its initial velocity (u) is 0 m/s since it starts from rest. The acceleration (a) is given as 3 m/s^2, and the time (t) is 4 seconds.
Plugging in these values into the equation, we have:
v = 0 + 3 * 4
v = 0 + 12
Therefore, the velocity gained by the aircraft in 4 seconds is 12 m/s.