suppose you have an unlimited supply of copper (II) chloride to react with iron. How many moles of copper would be produced by reacting 34 grams of iron with the copper(II) chloride solution?
Here is a sample stoichiometry problem I posted. Just follow the steps.
http://www.jiskha.com/science/chemistry/stoichiometry.html
To determine the number of moles of copper produced by reacting 34 grams of iron with copper(II) chloride, we need to follow these steps:
Step 1: Determine the molar mass of iron (Fe)
The molar mass of iron is found on the periodic table and is approximately 55.85 g/mol.
Step 2: Convert the mass of iron to moles
To convert grams to moles, divide the mass by the molar mass of iron:
34 g Fe / 55.85 g/mol = 0.61 mol Fe
Step 3: Determine the balanced chemical equation
The balanced chemical equation for the reaction between iron and copper(II) chloride is:
2 Fe + 3 CuCl2 → 3 Cu + 2 FeCl3
Step 4: Use the stoichiometry of the balanced chemical equation to determine moles of copper produced
From the balanced chemical equation, we can see that 2 moles of iron react with 3 moles of copper chloride to produce 3 moles of copper. Therefore, the mole ratio is:
2 mol Fe : 3 mol Cu
Using this ratio, we can determine the number of moles of copper produced:
0.61 mol Fe × (3 mol Cu / 2 mol Fe) = 0.92 mol Cu
Therefore, by reacting 34 grams of iron with copper(II) chloride, approximately 0.92 moles of copper would be produced.
To determine the number of moles of copper produced, you need to follow a few steps:
Step 1: Write and balance the chemical equation for the reaction between iron and copper(II) chloride:
2 Fe + 3 CuCl2 → 2 FeCl3 + 3 Cu
This equation tells us that 2 moles of iron react with 3 moles of copper(II) chloride to produce 3 moles of copper.
Step 2: Calculate the molar mass of iron (Fe) and copper(II) chloride (CuCl2):
- Molar mass of Fe = 55.85 g/mol
- Molar mass of CuCl2 = (63.55 g/mol for Cu) + (2 * 35.45 g/mol for Cl) = 134.45 g/mol
Step 3: Convert the given mass of iron to moles:
- Moles of Fe = Given mass (34 g) / Molar mass of Fe
Step 4: Determine the moles of copper using the mole ratio from the balanced equation:
- Moles of Cu = Moles of Fe * (3 moles of Cu / 2 moles of Fe)
Now, let's calculate the answer:
Moles of Fe = 34 g / 55.85 g/mol ≈ 0.609 mol
Moles of Cu = 0.609 mol * (3 mol of Cu / 2 mol of Fe) ≈ 0.914 mol
Therefore, reacting 34 grams of iron with the copper(II) chloride solution would produce approximately 0.914 moles of copper.