The average mark on a test in an algebra class is 80. If the two lowest scores of 34 and 48 are not counted, the remaining scores would average 83. How many students are in the algebra class?

To solve this problem, we'll need to set up equations based on the information given and then solve for the unknown variable, which represents the number of students in the algebra class.

Let's assume that there are 'n' students in the algebra class.

First, we know that the average mark on a test in the algebra class is 80. This means that the sum of all the test scores is equal to 80 times the number of students, which can be represented as:

Total marks = 80n

Next, we are told that if the two lowest scores of 34 and 48 are not counted, the remaining scores would average 83. Since there are 'n' students, and we are excluding the lowest two scores, the sum of the remaining scores would be (n-2) times 83, which can be represented as:

Remaining marks = 83(n-2)

We can now set up an equation using the information given:

Total marks - (34 + 48) = Remaining marks
80n - 82 = 83(n-2)

We can solve this equation to find 'n', the number of students:

80n - 82 = 83n - 166
166 - 82 = 83n - 80n
84 = 3n
n = 84/3
n = 28

Therefore, there are 28 students in the algebra class.