I need the molecular, ionic and net ionic equation for copper (II) acetate and sodium carbonate......help!
Sure! I can help you with that. To determine the molecular, ionic, and net ionic equations for the reaction between copper (II) acetate and sodium carbonate, we first need to know the formulas for these compounds.
The formula for copper (II) acetate is Cu(CH3COO)2, and the formula for sodium carbonate is Na2CO3.
Now let's break down the reaction into ionic equations:
1. Molecular Equation:
Cu(CH3COO)2 + Na2CO3 -> CuCO3 + 2CH3COONa
2. Ionic Equation:
Cu2+ + 2CH3COO- + 2Na+ + CO3^2- -> CuCO3 + 2CH3COONa
In the ionic equation, we separate all the soluble compounds into their individual ions.
3. Net Ionic Equation:
Cu2+ + CO3^2- -> CuCO3
The net ionic equation is obtained by removing the spectator ions (ions that appear on both sides of the equation and do not participate in the reaction) from the ionic equation.
So, the molecular equation is Cu(CH3COO)2 + Na2CO3 -> CuCO3 + 2CH3COONa,
the ionic equation is Cu2+ + 2CH3COO- + 2Na+ + CO3^2- -> CuCO3 + 2CH3COONa, and
the net ionic equation is Cu2+ + CO3^2- -> CuCO3.
I hope this helps! Let me know if you have any further questions.