Find the standard form of the equation of the circle.
3(x+2)^2 + 3(y-1)^2=18
so i used this formula
r^2 = (x+h^)2 + 3(y+k)^2
i just plug in the number but what do i do with the 3's outside of the parenthesis or i have to do something else...
divide each side by 3 to get standard form.
To find the standard form of the equation of the circle, you're on the right track with using the formula for a circle, which is:
r^2 = (x - h)^2 + (y - k)^2
In the given equation 3(x+2)^2 + 3(y-1)^2 = 18, you have the 3's outside of the parentheses. To convert this equation into standard form, you need to divide the entire equation by 3 to remove the coefficient of the terms:
(x+2)^2 + (y-1)^2 = 6
Now, the equation is in standard form with the center of the circle at (-2, 1) and the radius squared, r^2, equal to 6.