Find the standard form of the equation of the circle.

3(x+2)^2 + 3(y-1)^2=18

so i used this formula
r^2 = (x+h^)2 + 3(y+k)^2

i just plug in the number but what do i do with the 3's outside of the parenthesis or i have to do something else...

divide each side by 3 to get standard form.

To find the standard form of the equation of the circle, you're on the right track with using the formula for a circle, which is:

r^2 = (x - h)^2 + (y - k)^2

In the given equation 3(x+2)^2 + 3(y-1)^2 = 18, you have the 3's outside of the parentheses. To convert this equation into standard form, you need to divide the entire equation by 3 to remove the coefficient of the terms:

(x+2)^2 + (y-1)^2 = 6

Now, the equation is in standard form with the center of the circle at (-2, 1) and the radius squared, r^2, equal to 6.