3X+4Y<12 the inequality sign also has a line underneath
no. don't look for points yet. first, convert the given equation into slope-intercept form, y=mx+b,,
alright i'll help you in this one:
3x+4y<12
now to solve for y, transpose 3x to the right side of equation, but the sign becomes the opposite (positive 3x becomes -3x:
4y < 12 - 3x
then to get y alone, divide all terms by 4:
y < 12/4 - (3/4)x
y < 3 - (3/4)x or
y < (-3/4)x + 3 *slope intercept form*
now, find the x-intercept and y-intercept,, first treat this as
y = (-3/4)x + 3
to get x-intercept: let y = 0 and solve for x
to get y-intercept: let x = 0 and solve for y
let me see your work. :)
oh, so it's "less than or equal to"
you have to change this into y = mx + b (slope-intercept form), alright to do this, transpose 3x to the right side of equation, and divide everything by 4 to get y,,
let me see your answer for this first. :)
4y+3x=12 it also says that i have to graph it. If I graph the x on 4 and the y on 3 would that be correct if not where do i have to graph the coordinates at?
oh sorry it is supposed to be 3x+4y=12? right so where do i graph these at. what are the coordinates?
can you just give me the answer please
No, we do not give the answers here. That will not help you learn this.
3x + 4y =< 12.
We graph the ineguality by graphing the
boundary line:
Graph: 3x + 4y = 12.
Let x = 0:
3*0 + 4y = 12,
4y = 12,
y = 12 / 4 = 3,
P1(0 , 3).
Let y = 0:
3x + 4*0 = 12,
3x = 12,
x = 12 / 3 = 4.
P2(4 , 0).
Use these points for graphing:
P1(0 , 3) , P2(4 , 0).
Since your inequality includes an = sign, all points on the line should
satisfy the inequality. The < sign means that all points below the line
should satisfy the inequality also.