3X+4Y<12

solve for x or y?

or, do you need to graph it?

It just says solve it and then graph it...

to graph this, first convert this equation to slope-intercept form (y = mx + b),,

then graph it like a normal line (imagine the inequality sign to be equal sign),, since the sign is only "greater than" (>) or "less than" (<) (not greater than or equal to (>=))
the line must be a broken line / dashed line,,
then looking at your equation in slope-intercept form, if it's greater than, shade the upper part, and if less than, shade the lower part,,

so there,, hope this helps~

ITS ACTUALLY THE SYMBOL I GAVE WITH A LINE UNDER NEATH IT. i DO NOT UNDERSTAND THIS. PLEASE HELP ME.

please helop me!!!!

The given inequality is 3X + 4Y < 12. To understand how to solve this inequality, let's break it down step by step.

Step 1: Graph the equation 3X + 4Y = 12
Start by solving the equation 3X + 4Y = 12 for Y to identify the boundary line.
4Y = 12 - 3X
Y = (12 - 3X) / 4

Now, graph the equation Y = (12 - 3X) / 4. This line will represent the boundary of the inequality.

Step 2: Determine the inequality symbol
The inequality symbol < indicates that the shaded region should be below the boundary line. Therefore, we will shade the area below the line.

Step 3: Test a point
Since the inequality is strict (<), we need to test a point in either the shaded region or outside it to determine which side is valid. In this case, let's test the point (0, 0), which is easy to evaluate.
Plug in X = 0 and Y = 0 into the original inequality:
3(0) + 4(0) < 12
0 < 12

Since the inequality is true for the point (0, 0), we know that this region is the solution.

To summarize, the solution to the inequality 3X + 4Y < 12 is the shaded region below the boundary line formed by the equation 3X + 4Y = 12.