find the force exerted by the rope on the car when the angle is 2.9 degrees and you are pulling with a force of 384 N but the car does not move

The force exerted by the rope = 384 N @ 2.9 deg, but the force that tends to move the car = the hor. component of the force:

Fh = 384*cos2.9.

To find the force exerted by the rope on the car, we need to analyze the forces acting on the car. In this case, there are two main forces at play: the force you are exerting by pulling the rope and the force of friction opposing the motion of the car.

When the car does not move, the force exerted by the rope is equal in magnitude but opposite in direction to the force of friction. Therefore, to find the force exerted by the rope, we need to determine the force of friction.

The force of friction can be calculated using the equation:

Friction = μ * Normal force

where μ is the coefficient of friction between the tires of the car and the surface it is on, and Normal force is the perpendicular force exerted by the surface on the car (equal to the car's weight in this case).

Since the car is not moving, the force of friction must be equal to and opposite in direction to the force you exert on the rope. Therefore:

Force of friction = Force exerted by the rope = 384 N

Now, to calculate the magnitude of the force exerted by the rope on the car, we can use trigonometry. The angle of 2.9 degrees can be used to determine the component of the force exerted by the rope in the horizontal direction. This can be calculated using:

Horizontal component of force = Force exerted by the rope * cos(angle)

where cos(angle) is the cosine of the given angle.

Plugging in the values, we have:

Horizontal component of force = 384 N * cos(2.9 degrees)

Calculating this expression, we can find the horizontal component of force exerted by the rope on the car.