A child bounces a 46 g superball on the side-walk. The velocity change of the superball isfrom 28 m/s downward to 16 m/s upward.If the contact time with the sidewalk is1800s, what is the magnitude of the average forceexerted on the superball by the sidewalk?

Answer in units of N.

Also it's not 1800, it's 1/800

Also it's not 1800, it's 1/800

so it would be: .046kg * 44 = 2.024
2.024/(1/800)

It should equal = 1619.2
Check your answer but that should be it, especially if they're asking you in units of N

i got 1.124 nd it said it was wrong

force*1800s=46*44
force*1800s=2024
force=1.12444444

The problem with your answe was that you didn't convert the grams to kg

To find the magnitude of the average force exerted on the superball by the sidewalk, we can use Newton's second law of motion, which states that force is equal to the rate of change of momentum.

The momentum of an object is given by the product of its mass and velocity. In this case, the change in momentum of the superball can be calculated as:

Change in momentum = (mass of the superball) × (final velocity - initial velocity)

The mass of the superball is given as 46 g, which is equivalent to 0.046 kg. The initial velocity is 28 m/s downward and the final velocity is 16 m/s upward. Remember, we need to consider the direction of the velocities when calculating the change in momentum.

Change in momentum = (0.046 kg) × (16 m/s upward - (-28 m/s downward))

To simplify the calculation, we can subtract the negative velocity:

Change in momentum = (0.046 kg) × (16 m/s + 28 m/s)

Now we have the change in momentum. Remember that the contact time with the sidewalk is given as 1800 s. The rate of change of momentum is the force exerted over a certain time period.

Average force = Change in momentum / Contact time

Average force = [(0.046 kg) × (16 m/s + 28 m/s)] / 1800 s

Calculating this expression will give us the magnitude of the average force exerted on the superball by the sidewalk.

force*time= mass*changevelocity

= mass*(16-(-28)

find force.