Question

factorise

9x^2-29x+34

thanks

Answer 1

since it is not factorable, use quadratic formula:

x = [-b +- sqrt(b^2-4ac)]/(2a)
where a = 9, b=-29, c=34
x = [29 +- sqrt(29^2 - 4*9*34)]/(2*9)
x = [29 +- sqrt(841 - 1224)]/18
x = [29 +- sqrt(-383)]/18
thus, the roots are:
x = [29 + i*sqrt(383)]/18 ; and
x = [29 - i*sqrt(383)]/18

therefore,
(x-[29 + i*sqrt(383)]/18)(x-[29 - i*sqrt(383)]/18)

so there,, :)