find x
x^2-3x-4 = x^2 +11x+24
please can you show me you method
thanks
the x^2 will cancel
-3x - 11x = 24 + 4
-14x = 28
x = -2
x^2-3x-4-x^2-11x=24+4
-14x=28 Divided with -14
x=28/(-14)=-2
To solve for x in the given equation, we need to simplify and isolate the x terms on one side of the equation.
Step 1: Bring all the x terms to one side of the equation by subtracting x^2 and 11x from both sides:
(x^2 - x^2) - 3x - 11x - 4 = 0 + 11x + 24
Simplifying this gives us:
-14x - 4 = 11x + 24
Step 2: Move the constant terms to the other side of the equation by adding 4 to both sides:
-14x - 4 + 4 = 11x + 24 + 4
Simplifying, we have:
-14x = 11x + 28
Step 3: Combine like terms by adding 14x to both sides:
-14x + 14x = 11x + 14x + 28
This simplifies to:
0 = 25x + 28
Step 4: Move 28 to the other side by subtracting it from both sides:
0 - 28 = 25x + 28 - 28
Simplifying gives us:
-28 = 25x
Step 5: Solve for x by dividing both sides of the equation by 25:
-28/25 = 25x/25
This simplifies to:
x = -28/25
Therefore, the value of x that satisfies the equation is x = -28/25.