It takes 51.0 j to raise the temperature of an 8.60 g piece of unknown metal from 13.0 C to 25.0 C. What is the specific heat for the metal?
Q = mc(T2-T1)
where Q = heat in J, m = mass in kg, c = specific heat capacity in J/(g*K), T = temperature in Kelvin,,
**change in temperature can have unit degree Celsius or Kelvin,, thus you can use it interchangeably (what i mean is that the units for c can also be J/(g*C))
therefore:
51 = 8.6*c*(25-13)
c = 0.494 J/g*K
(always check significant figures)
so there,, :)
A 15.7g block of an unknown metal is warmed to 53.2o C and plunged into an insulated beaker containing 32.5g of water initially at 24.5o C. The metal block and water are allowed to come to thermal equilibrium and the final temperature of the system is 27.2oC. Assuming that no heat is lost, find the specific heat of the mystery metal block and specify the identity of the metal.
To find the specific heat of the metal, we can use the formula:
Q = mcΔT
Where:
Q = heat energy (in joules)
m = mass of the metal (in grams)
c = specific heat of the metal (in J/g°C)
ΔT = change in temperature (in °C)
In this case, we know:
Q = 51.0 J
m = 8.60 g
ΔT = 25.0°C - 13.0°C = 12.0°C
Substituting the given values into the formula, we have:
51.0 J = (8.60 g) × c × 12.0°C
First, let's simplify the equation:
612 g·°C = 8.60 g × c × 12.0°C
To solve for c, we can divide both sides of the equation by (8.60 g) × 12.0°C:
c = 612 g·°C / (8.60 g × 12.0°C)
Now, we can calculate the specific heat:
c = 6.009 g·°C/g
Therefore, the specific heat for the metal is approximately 6.009 J/g°C.
To find the specific heat for the metal, we need to use the formula:
q = mcΔT
Where:
q = heat energy (in joules)
m = mass of the metal (in grams)
c = specific heat capacity of the metal (in joules/gram °C)
ΔT = change in temperature (final temperature - initial temperature in °C)
In this case, the heat energy (q) is given as 51.0 J, the mass (m) is 8.60 g, the initial temperature is 13.0 °C, and the final temperature is 25.0 °C.
So, let's plug in the given values into the formula and solve for c:
51.0 J = (8.60 g) * c * (25.0 °C - 13.0 °C)
First, calculate the change in temperature:
ΔT = 25.0 °C - 13.0 °C = 12.0 °C
Now, rearrange the formula to solve for c:
c = q / (m * ΔT)
Substitute the known values:
c = 51.0 J / (8.60 g * 12.0 °C)
Now, calculate the specific heat:
c = 0.625 J/g°C
Therefore, the specific heat for the metal is 0.625 joules/gram °C.