In a triangle ABC, angle B is three times angle A and angle C is 1 less than 6 times angle A. Find the size of angle A, B, C

B=3A , C=6A-1

Sum of angles in triangle is 180°
A+B+C=180°
A+3A+6A-1=180
10A-1=180,
10A=180+1=181 Divided with 10
A=18.1°
B=3A= 3*18.1=54.3°
C=6A-1= 6*18.1-1=108.6-1=107.6°

A=18.1°=18+(0.1*60)= 18° 6´
Besouse 1°= 60´
B=54.3°=54+(0.3*60)= 54° 18´
C=107.6°=107+(0.6*60)= 107° 36´

whai is cbd is 70 then what is angle abc is

To solve this problem, we can use the fact that the sum of the angles in a triangle is always 180 degrees. Let's proceed step by step:

1. Let's start by assigning a variable to angle A. Let's call it "x". So angle A is x degrees.
2. According to the problem, angle B is three times angle A. Therefore, angle B is 3x degrees.
3. Angle C is 1 less than 6 times angle A. So angle C is 6x - 1 degrees.
4. The sum of the angles in a triangle is always 180 degrees. Therefore, we can write the following equation:
x + 3x + 6x - 1 = 180
5. Simplify the equation:
10x - 1 = 180
6. Add 1 to both sides of the equation:
10x = 181
7. Finally, divide both sides of the equation by 10:
x = 18.1

After solving the equation, we found that angle A is 18.1 degrees. Now, we can substitute this value back into the expressions for angles B and C to find their sizes.

Angle B = 3x = 3 * 18.1 = 54.3 degrees
Angle C = 6x - 1 = 6 * 18.1 - 1 = 108.6 - 1 = 107.6 degrees

Therefore, angle A is 18.1 degrees, angle B is 54.3 degrees, and angle C is 107.6 degrees.