Calculate the concentration of H3O+ that contains 5.5 x 10 ^-5 moles/L OH- at 25 degrees
To find the concentration of H3O+, we can use the fact that water dissociates into H3O+ and OH- ions according to the equation:
H2O ⇌ H3O+ + OH-
At 25 degrees Celsius, the autoionization constant of water (Kw) is equal to 1.00 x 10^-14 mol^2/L^2. This constant can be used to determine the concentrations of the ions.
Given that the concentration of OH- is 5.5 x 10^-5 mol/L, we can use Kw to calculate the concentration of H3O+.
Step 1: Write the Kw expression.
Kw = [H3O+][OH-]
Step 2: Substitute the given values.
1.00 x 10^-14 mol^2/L^2 = [H3O+][5.5 x 10^-5 mol/L]
Step 3: Solve for [H3O+].
[H3O+] = (1.00 x 10^-14 mol^2/L^2) / (5.5 x 10^-5 mol/L)
Step 4: Simplify the equation.
[H3O+] ≈ 1.82 x 10^-10 mol/L
Therefore, the concentration of H3O+ is approximately 1.82 x 10^-10 mol/L.
To calculate the concentration of H3O+ in a solution, you need to use the concept of the ion product of water, also known as Kw.
The ion product of water (Kw) is a constant value at a given temperature. At 25 degrees Celsius, Kw is approximately equal to 1.0 x 10^-14.
Kw is defined as the product of the concentrations of H3O+ and OH- ions in water:
Kw = [H3O+][OH-]
Given that the concentration of OH- is 5.5 x 10^-5 moles/L, we can use this information to find the concentration of H3O+.
Rearranging the equation above, we get:
[H3O+] = Kw / [OH-]
Plugging in the values:
[H3O+] = (1.0 x 10^-14) / (5.5 x 10^-5)
Calculating this expression, we find:
[H3O+] ≈ 1.8 x 10^-10 moles/L
Therefore, the concentration of H3O+ is approximately 1.8 x 10^-10 moles/L at 25 degrees Celsius.