Hello. I am trying to figure out how to find the number of solutions in the following problem:
(x + 8) (x + 8) = 0
Hello! To find the number of solutions in the equation (x + 8)(x + 8) = 0, we can first simplify the equation by applying the distributive property:
(x + 8)(x + 8) = 0
(x + 8)(x) + (x + 8)(8) = 0
x^2 + 8x + 8x + 64 = 0
x^2 + 16x + 64 = 0
Now, we have a quadratic equation in the form ax^2 + bx + c = 0, where a = 1, b = 16, and c = 64. To determine the number of solutions, we can use the discriminant formula:
Discriminant (D) = b^2 - 4ac
Plugging in the values, we get:
D = 16^2 - 4(1)(64)
D = 256 - 256
D = 0
The discriminant (D) equal to 0 indicates that there is only one real solution. In this case, the equation (x + 8)(x + 8) = 0 has one solution.