Which best describes the relationship between the lines with equations -16x+2y=0 and -x-8y=-2?
a. neither parallel nor perpendicular
b. parallel
c. same line
d. perpendicular
The slope of the first line on a y vs x graph is 8. The slope of the second line is -1/8
Using the rule that I explained in your last question about the product of the two slopes, you should be qble to figure out the answer.
so the answer must be A right
No. d
Reread my other answer.
To determine the relationship between the two lines with equations -16x+2y=0 and -x-8y=-2, we need to analyze their slopes.
The equation of a line can be written in slope-intercept form: y = mx + b, where m represents the slope of the line.
For the first equation, -16x+2y=0, we isolate y to form: 2y = 16x and divide both sides by 2, giving us y = 8x. The slope of this line is 8.
For the second equation, -x-8y=-2, we isolate y to form: -8y = x - 2 and divide both sides by -8, giving us y = (1/8)x + (1/4). The slope of this line is 1/8.
Now that we have determined the slopes of the two lines, we can analyze their relationship:
- If two lines have the same slope, they are parallel. However, the slopes of these two lines, 8 and 1/8, are not the same.
- If two lines have slopes that are negative reciprocals of each other (i.e., the product of their slopes is -1), they are perpendicular. However, the product of 8 and 1/8 is not -1.
Therefore, the two lines with equations -16x+2y=0 and -x-8y=-2 are neither parallel nor perpendicular. The correct answer is a. neither parallel nor perpendicular.