How many grams are required to make 1.5 L of 3.0 M hydrochloric acid (HCl) solution?
See your other post above.
1.44
To find the number of grams required to make the given hydrochloric acid solution, you will need to follow a few steps. Here's how you can calculate it:
Step 1: Determine the molar mass of hydrochloric acid (HCl).
The molar mass of HCl can be calculated by adding the atomic masses of hydrogen (H) and chlorine (Cl). The atomic mass of hydrogen is approximately 1.01 g/mol, and the atomic mass of chlorine is approximately 35.45 g/mol. Therefore, the molar mass of HCl is 1.01 + 35.45 = 36.46 g/mol.
Step 2: Determine the number of moles of HCl required.
To find the number of moles needed, you can use the formula:
moles = molarity × volume
Given that the volume is 1.5 L and the molarity is 3.0 M, the number of moles of HCl can be calculated as follows:
moles = 3.0 M × 1.5 L = 4.5 moles
Step 3: Calculate the mass of HCl.
To calculate the mass of HCl, you need to multiply the number of moles by the molar mass of HCl (from step 1):
mass = moles × molar mass
mass = 4.5 moles × 36.46 g/mol = 164.07 grams
Therefore, approximately 164.07 grams of hydrochloric acid (HCl) are required to make a 1.5 L solution with a concentration of 3.0 M.