what would happen to the volume of the 100-L weather balloon if its temperature increases from 25 degrees Celsius to 125 degrees Celsius while the external pressure remains constant? Again, there are no leaks in the balloon.
(V1/T1)= (V2/T2)
To determine what would happen to the volume of the weather balloon when its temperature increases from 25 degrees Celsius to 125 degrees Celsius, we can use the ideal gas law.
The ideal gas law equation is:
PV = nRT
Where:
P = pressure
V = volume
n = number of moles of gas
R = ideal gas constant
T = temperature in Kelvin
In this case, we can assume that the external pressure remains constant, which means that the pressure in the balloon remains the same throughout the process. This allows us to simplify the equation:
V1 / T1 = V2 / T2
Where:
V1 = initial volume (100 L)
T1 = initial temperature (25°C + 273.15 = 298.15 K)
V2 = final volume (unknown)
T2 = final temperature (125°C + 273.15 = 398.15 K)
Now, we can solve for V2:
V2 = V1 * (T2 / T1)
= 100 L * (398.15 K / 298.15 K)
≈ 133.57 L
Therefore, if the temperature of the 100-L weather balloon increases from 25 degrees Celsius to 125 degrees Celsius, while the external pressure remains constant, its volume would increase to approximately 133.57 liters.