the small cylinder of a hydraulic press has an area of 2"(squared). If a force of 10# is applied to the small piston, how much is the pressure within the larger cylinder increased, according to pascal's principle.
is that, "force of 10 lbf"? if it is,
pressure is force per unit area, or:
P = F/A
P = 10 lbf/2 in^2
P = 5 psi (pounds per square inch)
so there,, :)
To determine how much the pressure within the larger cylinder is increased according to Pascal's principle, we need to understand the relationship between the force and the area of the cylinders.
Pascal's principle states that when pressure is applied to a fluid in a confined space, the pressure is transmitted equally in all directions. In the case of a hydraulic press, this means that the force applied to one piston is transmitted to the other piston, resulting in an increase in pressure in the larger cylinder.
Let's calculate the pressure increase step by step:
1. Determine the force applied to the small piston: The given force is 10#.
2. Calculate the area of the small piston: The area is given as 2"².
3. Convert the area to square inches: Since the area is given in square inches, no conversion is necessary.
4. Calculate the pressure on the small piston: Pressure is calculated by dividing the force by the area. So, pressure = force / area. In this case, pressure = 10# / 2"².
5. Determine the corresponding pressure increase in the larger cylinder: According to Pascal's principle, the pressure increase will be the same as the pressure applied to the small piston.
Therefore, the pressure within the larger cylinder will also be 10# per square inch.
In conclusion, according to Pascal's principle, the pressure within the larger cylinder will increase by 10# per square inch when a force of 10# is applied to the small piston.