write a balanced net ionic equation fir the reactions that occurred with the metal

Mg reacting with Pb2+

Mg + Pb-> PbMg

The post by Don is incorrect.

Mg(s) + Pb^+2(aq) ==> Mg^+2(aq) + Pb(s)

Oh sorry! I didn't read the net ionic part.

To write a balanced net ionic equation for the reaction between Mg and Pb2+, we need to first determine the chemical formulas and charges of the species involved.

- The symbol for magnesium is "Mg," and it has a charge of +2.
- The symbol for lead (II) ion is "Pb2+," indicating that it carries a charge of +2.

Now we can proceed with writing the net ionic equation:

Step 1: Write the balanced molecular equation
Mg + Pb2+ → Mg2+ + Pb

Step 2: Identify the spectator ions
In this case, there are no spectator ions, as all the species involved directly participate in the reaction.

Step 3: Write the net ionic equation
The net ionic equation is obtained by excluding the spectator ions from the molecular equation:
Mg + Pb2+ → Mg2+ + Pb

This is the balanced net ionic equation for the reaction between Mg and Pb2+.