write a balanced net ionic equation fir the reactions that occurred with the metal
Mg reacting with Pb2+
Mg + Pb-> PbMg
The post by Don is incorrect.
Mg(s) + Pb^+2(aq) ==> Mg^+2(aq) + Pb(s)
Oh sorry! I didn't read the net ionic part.
To write a balanced net ionic equation for the reaction between Mg and Pb2+, we need to first determine the chemical formulas and charges of the species involved.
- The symbol for magnesium is "Mg," and it has a charge of +2.
- The symbol for lead (II) ion is "Pb2+," indicating that it carries a charge of +2.
Now we can proceed with writing the net ionic equation:
Step 1: Write the balanced molecular equation
Mg + Pb2+ → Mg2+ + Pb
Step 2: Identify the spectator ions
In this case, there are no spectator ions, as all the species involved directly participate in the reaction.
Step 3: Write the net ionic equation
The net ionic equation is obtained by excluding the spectator ions from the molecular equation:
Mg + Pb2+ → Mg2+ + Pb
This is the balanced net ionic equation for the reaction between Mg and Pb2+.