write a net ionic equation for the following:
1)Iron (III) chloride reacts with Potassium hydroxide to produce Iron (III) oxide, Potassium chloride, and Hydrogen gas.
2)Hydrochloric acid reacts with Potassium carbonate to produce Potassium chloride, Hydrogen gas and Carbon dioxide.
1) FeCl3 + 3KOH → Fe2O3 + 3KCl + 3H2
2) 2HCl + K2CO3 → 2KCl + H2 + CO2
To write net ionic equations, you need to first write the balanced molecular equation, then dissociate the soluble compounds into their respective ions, and finally cancel out the spectator ions to obtain the net ionic equation.
Let's write the net ionic equations for the given reactions:
1) Iron (III) chloride reacts with Potassium hydroxide:
First, write the balanced molecular equation:
FeCl3 + 3 KOH → Fe(OH)3 + 3 KCl
Next, dissociate the soluble compounds into their respective ions:
FeCl3(aq) + 3 KOH(aq) → Fe(OH)3(s) + 3 KCl(aq)
Finally, cancel out the spectator ions (those present on both sides of the equation) to obtain the net ionic equation:
Fe^3+(aq) + 3 OH^-(aq) → Fe(OH)3(s)
2) Hydrochloric acid reacts with Potassium carbonate:
Start with the balanced molecular equation:
2 HCl + K2CO3 → 2 KCl + H2 + CO2
Next, dissociate the soluble compounds into their respective ions:
2 HCl(aq) + K2CO3(aq) → 2 KCl(aq) + H2(g) + CO2(g)
Finally, cancel out the spectator ions to obtain the net ionic equation:
2 H^+(aq) + 2 Cl^-(aq) + CO3^2-(aq) → 2 K^+(aq) + 2 Cl^-(aq) + H2(g) + CO2(g)
In the net ionic equation, we can see that H+ ions and Cl- ions are present on both sides and can be canceled out. Therefore, the final net ionic equation is:
H^+(aq) + CO3^2-(aq) → H2(g) + CO2(g)
1) The first step is to write the balanced molecular equation:
FeCl3 + 3KOH -> Fe2O3 + 3KCl + 3H2O
Next, we need to identify the soluble compounds and break them down into their respective ions. In this case, FeCl3 and KOH will dissociate into their respective ions:
Fe3+ + 3Cl- + 3K+ + 3OH- -> Fe2O3 + 3K+ + 3Cl- + 3H2O
After identifying the spectator ions (ions that appear on both sides of the equation), we can eliminate them from the equation. In this case, the K+ and Cl- ions are spectator ions:
Fe3+ + 3OH- -> Fe2O3 + 3H2O
Finally, we can simplify the remaining equation to write the net ionic equation:
Fe3+ + 3OH- -> Fe2O3 + 3H2O
2) Similarly, let's start with the balanced molecular equation:
2HCl + K2CO3 -> 2KCl + H2 + CO2
Next, we identify the soluble compounds and break them down into their respective ions. In this case, HCl and K2CO3 will dissociate into their respective ions:
2H+ + 2Cl- + 2K+ + CO3(2-) -> 2K+ + 2Cl- + H2 + CO2
Eliminating the spectator ions (K+ and Cl-):
2H+ + CO3(2-) -> H2 + CO2
Simplifying the remaining equation, we get the net ionic equation:
2H+ + CO3(2-) -> H2 + CO2