What volume of each of the following solutions contains 0.13mol of KCl?
1).345M of KCl
2)2.0M of KCl
3).895M of KCl
Remember the definition of molarity.
M = moles/L. You know moles and you know M, solve for L.
To find the volume of each solution that contains 0.13 mol of KCl, we can use the formula:
Volume = (Number of moles of solute) / (Concentration)
Let's calculate the volume for each solution:
1) For a 0.345 M solution of KCl:
Volume = 0.13 mol / 0.345 mol/L
Volume = 0.3768 L or 376.8 mL
Therefore, to have 0.13 mol of KCl in a 0.345 M solution, you would need approximately 376.8 mL of the solution.
2) For a 2.0 M solution of KCl:
Volume = 0.13 mol / 2.0 mol/L
Volume = 0.065 L or 65 mL
Therefore, to have 0.13 mol of KCl in a 2.0 M solution, you would need approximately 65 mL of the solution.
3) For a 0.895 M solution of KCl:
Volume = 0.13 mol / 0.895 mol/L
Volume = 0.145 L or 145 mL
Therefore, to have 0.13 mol of KCl in a 0.895 M solution, you would need approximately 145 mL of the solution.