How would I find the moles of H+ if I have 2.0 M HCl and 2.0 M NaOH solution?
If separate solutions, moles = M x L.
So, if I mixed them together, would I take the total volume of the solution and multiply it by 4 M, or just keep it as 2 M?
If you mix them, then
M HCl x L HCl = moles HCl
M NaOH x L NaOH = moles NaOH.
What's left depends upon how many moles of each solution we had. These react 1:1; therefore, larger moles - smaller moles = moles left, then H^+ or OH^- (depending upon which is in excess) = moles/total L.
To find the number of moles of H+ in a solution, you need to know the concentration of H+ ions. In this case, you have a 2.0 M HCl (hydrochloric acid) solution.
The number of moles can be calculated using the formula:
moles = concentration (M) × volume (L)
However, since HCl is a strong acid and completely dissociates in water, the concentration of H+ is the same as the concentration of the HCl solution. Therefore, in this case, the concentration of H+ is 2.0 M.
To find the number of moles of H+ in the solution, you would need to know the volume of the solution. Assuming you have the volume of the solution, you can calculate the moles of H+ using the above formula.
Please note that if you are performing a neutralization reaction between HCl and NaOH, the number of moles of H+ would be equal to the number of moles of NaOH used (assuming a 1:1 stoichiometric ratio between H+ and OH- ions).