The drama club raised a total of $1,123.50 selling

tickets to its production of Othello. Tickets cost $4.50
for adults and $2.00 for students. Three times as
many student tickets were sold as adult tickets.
Which system of equations can be used to find a, the
number of adult tickets sold, and s, the number of
student tickets sold?

a = The number of adult tickets sold.

s = 3a = the # of student tickets sold.

4.5a + 3a*2.0 = 1123.50.
10.5a = 1123.50,
a = 107.

s = 3a = 3*107 = 321.

Thanks Henry

At the city museum, child admission is and adult admission is . On Friday, four times as many adult tickets as child tickets were sold, for a total sales of . How many child tickets were sold that day?

To find the number of adult tickets (a) and the number of student tickets (s) sold, we can set up a system of equations.

Let's start by defining the variables:
a = number of adult tickets sold
s = number of student tickets sold

We know the total amount raised was $1,123.50, so we can create an equation based on that information:
4.50a + 2.00s = 1123.50

We're also given that three times as many student tickets were sold as adult tickets. Since "three times as many" means multiplying by 3, we can create another equation:
s = 3a

So the system of equations is:
4.50a + 2.00s = 1123.50
s = 3a

Now we can solve this system of equations to find the values of a and s.